The balanced equation is: NaOH (aq) + HCl (aq) NaCl (aq) + H 2O (l) So the mole ratio NaOH:HCl is 1:1. How many moles of NaOH were consumed in this trial? The NaOH(aq) solution is then titrated against 0.1038 g In order to determine the exact concentration of a sodium hydroxide solution you must standardize it by titrating with a solid acid that is not hygroscopic. To get the molar amount of acid used for the experiment, use its molar mass 0.5100g molar mass of KHP 1 mole KHP 204.22g = 0.0024973 moles KHP So, you know that at equivalence point, the reaction will consume 0.0024973 moles of KHP and 0.0024973 moles of NaOH, since that's what the 1:1 mole ratio tells you. To achieve this first calculate the number of moles of KHP present in the trial. Also, the % uncertainty of the volume of NaOH was 1.05%, taking the value of 9.50 cm3. Choose one fine trial done, and use it to You start with 0.5100 g of KHP . From mole ratio, number of moles of NaOH = 0.00979 mol. A 0.8234-g sample of KHP required 38.76 mL of NaOH for titration to the phenolphthalein endpoint. Nam lacinia pulvinar tortor nec facilisis. The manufacture of soap requires a number of chemistry techniques. Therefore, one mole of KHP reacts with one mole of NaOH: KHC8H404 (aq) + NaOH (aq) NakCxH404 (aq) + H2O (1). 2 0 obj Now, that's different than asking about pH values in the solution, since the actual [H3O(1+)] level is affected by the various equilibrium reactions the salt ions nominally present may have undergone. Finally, divide the moles of \(\ce{H_2SO_4}\) by its volume . From the mole ratio, calculate the moles of \(\ce{H_2SO_4}\) that reacted. accurately known masses of KHP. stream And where they cross over youre going to go to roughly the midpoint. In short, titration is all about "theoretical, complete" reactions. Nam lacinia, usce dui lectus, congue vel laoreet ac, dictum vitae odio. eqn. stream Procedure The experiment consisted of three separate parts: the standardization of NaOH using the acid KHP, the determination of an acetic acid solution's molarity using the standardized NaOH, and using the same NaOH to find a sulfuric acid solution's molarity. molecular equation: KHC8H4O4(aq) + NaOH (aq) KNaC8H4O4(aq) + H2O(l) A Chem 1515 student dissolved 0.33 grams of KHP in 25.0 mL of water. At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water. Nam lacinia pulvinar tortor, inia pulvinar tortor nec facilisis. What is the balanced chemical equation for NaOH and KHP? Convert grams NaOH to moles - Conversion of Measurement Units The important thing to notice here is that you have a #1:1# mole ratio between the two reactants. (NaOH) = ( g KHP)( 1 mol KHP / 204.23 g) ( 1 mol NaOH / 1 mol KHP) / (V L of NaOH) (0.905 g KHP) ( 1mol KHP ) ( 1mol __ ) = 0.00443 . In this case, you are looking for the concentration of hydrochloric acid (its molarity): Because the ratio betweenC8H5KO4 and NaOH is one to one you will need the same number of moles of NaOH as KHP to reach the equivalence point. Or, if you type your answers, PDF Experiment 6: STANDARDIZATION OF A BASE; MASS PERCENT OF AN ACID Type of Acid/Base Indicator used Phenolphthalein. You can calculate the percent error by using the formula, #color(blue)("% error" = (|"approximate value" - "exact value"|)/"exact value" xx 100)#, #"% error" = (|0.07878 - 0.100|)/0.100 xx 100 = 21.22%#. Nam lacinia pulvinar t, facilisis. Nam risus ante, dapibus a molestie consequat, ultr, at, ultrices ac magna. Donec aliquet. How can you determine the strength of sulfuric acid? We pay $$$ and it takes seconds! [NaOH) - mol/L Calculation for Trial 2. The volumes of NaOH used up show significant fluctuations. So, assuming KHP is potassium hydrogen phthalate, we have the following reaction: NaOH + C 8 H 5 KO 4 ==> H 2 O + C 8 H 4 NaKO 4 molar mass KHP = 204 g/mole Nam lacinia pulvinar tortor nec facilisis. Molarity of NaOH = (mol KHP)/ (V NaOH used for titration): M(NaOH)=0,00213mol0,03103L=0,0688molL . 1.54g of KHP is equivalent to 0.00754 mol of KHP. You know the number of moles of NaOH, because it's the same as the number of moles of KHP. Donec aliquet. converted to moles of KHP used in the reaction, and then the grams of KHP present in the previously weighed sample can be determined. Finally, use the volume of NaOH consumed in the trial to calculate the molarity of the NaOH. appropriate number of significant digits. Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. How do you calculate the molar mass of KHP? - Answers \[\text{M}_A = \frac{\text{M}_B \times \text{V}_B}{\text{V}_A} = \frac{0.500 \: \text{M} \times 20.70 \: \text{mL}}{15.00 \: \text{mL}} = 0.690 \: \text{M}\nonumber \]. Fusce dui lectus, congue vel laoreet ac, dictum v, itur laoreet. At the end point the solution pH is 8.42. endobj The molarity of the NaOH solution is Do not round off any intermediate results during this multi-step calculation . For Mastery on this assignment, you must Master 10 or more of these questions. point. KHP is a weak acid, and the equation for the neutralization of K P by NaOH is Potassium sodium phthalate COOK COOK NaOH + H2O + -COONa KHP Potassium hydrogen phthalate 1. 2.04/204= 0 moles, What is the molarity of the standard? Fusce dui lectus, congue vel laoreet ac, dictum vitae odio. When KHP and NaOH combine, a positive hydrogen ion leaves the KHC8H4O4 and a negative hydrogen atom leaves the NaOH. No packages or subscriptions, pay only for the time you need. The molar mass of KHP is approximately 204.22 g/mol. The grams required can be obtained by multiplying the moles of NaOH by the molecular weight of KHP. The NaOH may not have reacted with the exact amount of KHP expected. Only one of the hydrogen atoms in KHP has acidic properties. a. Nam lacinia, iscing elit. Conversely, for the titration of a weak base with strong acid, the pH at the equivalence point is less than 7 because only the conjugate acid is present. 35,000 worksheets, games, and lesson plans, Marketplace for millions of educator-created resources, Spanish-English dictionary, translator, and learning, Diccionario ingls-espaol, traductor y sitio de aprendizaje, a Question This might have caused some deviations because the volume of sodium hydroxide added was excess. Get a free answer to a quick problem. This will be a strong base - weak ac. This is easy. Convert grams KHP to moles - Conversion of Measurement Units Equivalence point of khp and naoh - The Equivalent Donec aliquet. Pell

Odesha D. In this case, 2 moles of NaOH are required to titrate 1 mole of H 2 SO 4. This is characteristic of a major error in your experiment. Liters NaOH sol'n used. With 0.2535 mmol/mL of NaOH, we need a volume of 4.166 mmol/(0.2535 mmol/mL)=16.43 mL. How do you predict the products in acid-base reactions? and KHP are equal and we used an indicator to find this point. Your online site for school work help and homework help. When the solution starts becoming dark pink abruptly, immediately reduce the rate of flow of NaOH from the burette, and after the pink can no longer be eliminated, shut off the supply. Number of moles of KHP in 2.00 grams = (m/M) = (2/204.22) mol = 0.00979 mol, Number of moles of KHP in 0.01 dm3 of solution in conical flask = [c] x V. From the mole ratio, the number of moles of NaOH = 0.00979 mol. <> This would have resulted in inaccuracies. How do you know? Nam risus ante, dapibus a molestie consequat, ultrices ac magna.ctum vitae odio. 1. Cross), Forecasting, Time Series, and Regression (Richard T. O'Connell; Anne B. Koehler), The Methodology of the Social Sciences (Max Weber), Educational Research: Competencies for Analysis and Applications (Gay L. R.; Mills Geoffrey E.; Airasian Peter W.), Introductory College Chemistry I Laboratory (CHEM 1411), Post Lab 4 1411 - Lab Report 4 for CHEM 1411 UVA, Introductory College Chemistry I Laboratory, Web Programming 1 (proctored course) (CS 2205), Art History I OR ART102 Art History II (ART101), Accounting Information Systems (ACCTG 333), Differential Diagnosis & Primary Care Practicum (NR-511), PHIL ethics and social responsibility (PHIL 1404), Managing Business Communications and Change (MGT-325), Fundamentals General, Organic, Biological Chemistry I (CHE 121), Professional Application in Service Learning I (LDR-461), Advanced Anatomy & Physiology for Health Professions (NUR 4904), Principles Of Environmental Science (ENV 100), Operating Systems 2 (proctored course) (CS 3307), Comparative Programming Languages (CS 4402), Business Core Capstone: An Integrated Application (D083), Student-HTN-Atherosclerosis Unfolding Reasoning, Summary Media Now: Understanding Media, Culture, and Technology - chapters 1-12. Donec aliquet. YouTubeYouTubeStart of suggested clipEnd of suggested clipAnd youre going to look at where they intersect or cross over rather not intersect. And where theyMoreAnd youre going to look at where they intersect or cross over rather not intersect. KHP Final burette reading. Determining Molarity Through Acid-Base Titration - Lab Report - Studocu How many liters (not mL) of NaOH were consumed in this titration? Then convert this to the number of moles of NaOH that were neutralized in the bitration (refer to balanced Eqn 1 shown in the lab manual). a) Calculate the concentration of the NaOH solution The expected % uncertainty that was expected was 0.500%, and the uncertainty I obtained was 0.503%. V of NaOH used =(31,26-0,23) = 31,03 mL = 0,03103 L mol NaOH = M V =M 0,03103 L but the mol of the two substance are the same therefore Molarity of NaOH = (mol KHP)/ (V NaOH used . From the mole ratio, calculate the moles of \(\ce{H_2SO_4}\) that reacted. Finally, divide the moles of \(\ce{H_2SO_4}\) by its volume to get the molarity. Answer in General Chemistry for Malathy #100482 Answer in General Chemistry for Brittany Wallace #96167 - Assignment Expert NaOH + C8H5KO4-->NaC8H4KO4 + H2O. It is not hygroscopic. Your goal here is to standardize a solution of sodium hydroxide, #"NaOH"#, by using potassium hydrogen phthalate, #"KHP"#. Nam lacinia pulvinar tortor nec facilisis, cing elit. Nam lacinia pulvinar tortor nec facilisis. A solution of sodium hydroxide is standardized against potassium Most questions answered within 4 hours. If you're using phenolphthalein as your indicator, an excess of sodium hydroxide would cause the solution to be a brighter shade of pink than it should be at equivalence point. titration problem | Wyzant Ask An Expert Nam lacinia pulvinar tortor nec facilisis. Answered: Data Table: Titration Part 1: Use the | bartleby Fxp yNptvy}Fwz(.m2ALXJBzcw:=mP-:|jXV>eEB/5 \3/vG~E,L.2iw$UT5? This way, we avoid excess NaOH from being added. Titration Lab: NaOH with Standardized solution of KHP KHP Titration Lab Report FINAL .pdf - Saikrupa Rajaramsiva 1.54g of KHP is equivalent to 0.00754 mol of KHP. If the concentration is different, it must be replaced. Therefore, one mole of KHP reacts with one mole of NaOH: KHC8H404(aq) + NaOH(aq) NakCxH404(aq) + H2O(1). Nam risus ante, dapibus a molestie consequat, ultrices ac ma, consectetur adipiscing elit. <> 17.20 ml of a solution of NaOH(aq). answered 07/11/19, Ph.D. University Professor with 10+ years Tutoring Experience.